Question

if A=60° B=30°, verify that: tan(A-B) = tanA-tanB/1+tanA tanB.​

Answer 1

Answer:

tan (60°-30°) = TanA-TanB / 1+Tan A TanB

Tan 30° = Tan 60°- Tan 30° / 1+ Tan 60° × Tan 30°

1/√3 = √3 - 1/√3 / 1+ √3×1/√3 ( i have marked the numerator with bold font)

1/√3 = (√3)²-1 /√3 /1 +1

1/√3 = 3-1 /√3 /2

1/√3 = 2/√3 /2

1/√3 = 2(1/√3) / 2

1/√3 = 1/√3

LHS = RHS