If A = 60° verify that: tan2A = 2tanA÷ 1- tan²A.
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tan2(60°)=2tan60°÷1-tan^2(60°)
tan120°=2√3÷{1-(√3)^2}
-√3 =2√3/(-2)
-√3. = -√3
i hope this will help u
tan120°=2√3÷{1-(√3)^2}
-√3 =2√3/(-2)
-√3. = -√3
i hope this will help u
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