Question

If a 60ml of water contains 12% of chlorine,how much water must be added in order to create 8% of chlorine solution

Answer 1

Answer:

9 ml

of water should be added in order to create 8% of chlorine solution

Explanation:

60ml water contains 12% water

=12×60/100 =7.2ml

8% of chlorine solution requires

8×60/100=4.8ml

60ml 7.2ml

xml 4.8ml (quantities are in inverse proportion therefore

60×7.2=4.8 × x

43.2=48×x

x= 43.2/4.8

=9ml

Answer 2

ɢɪᴠᴇɴ :

• total quantity of water is 60 ml
• contains 12% of chlorine

ᴛᴏ ғɪɴᴅ:

• the quantity of water must be added in order to create a 8% chlorine

sᴏʟᴜᴛɪᴏɴ :

Let x ml of chlorine be present in water.

Then, $\sf{\frac{12}{100} = \frac{x}{60}}$

→ x = $\sf{\frac{12}{100} × 60}$

→ x = 7.2 ml

Therefore, 7.2 ml is present in 60 ml of water.

In order for this 7.2 ml to constitute 8% of the solution, we need to add extra water. Let this be y ml.

Then, $\sf{\frac{8}{100} = \frac{7.2}{y}}$

→ y = 90 ml.

So in order to get a 8% chlorine solution, we need to add 90 - 60 = 30 ml of water.