If A = 6p square – 5q square,B = p square + 2q square ,then find the value of (3B – 4A) – (B – 6A)
step by step pls
Answers
Answer:
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Answer:
Step-by-step explanation:
Given that,
A = 6p² - 5q² and B = p²+ 2q²
3B - 4A= 3 (p² + 2q²) - 4 (6p² - 5q²)
= 3p²+ 6q²- ( 24p² - 20q²)
= 3p² + 6q² - 24p²+ 20q² ( ∵ - × + = - ; - × - = + )
= ( 3p² - 24p² ) + ( 6q² + 20q² ) ( ∵ like terms adding )
= - 21p² + 26q²
B - 6A = ( p² + 2q² ) - 6 ( 6p² - 5q² )
= p² + 2q² - ( 36p² - 30q² )
= p² + 2q²- 36p² + 30q² ( ∵ - × + = - : - × - = + )
= ( p² - 36p² ) + ( 2q² + 30q² )
= - 35p² + 32q²
∴ ( 3B - 4A ) - ( B - 6A ) = ( - 21p² + 26q² ) - ( - 35p² + 32q² )
= - 21p² + 26q² + 35p² - 32 q² ( ∵ - × - = + ; - × + = - )
= ( - 21p² + 35p² ) + ( 26q² - 32q² ) ( ∵ like terms adding )
= 14p² + ( - 6q² )
= 14p² - 6q² is the answer. ( ∵ + × - = - )