Math, asked by divyaniljikar, 11 months ago

if a^7=3 find the value of (a^-7)^-3*(a^3)^4*(a^-17)^-7/a^7​

Answers

Answered by 217him217
2

Step-by-step explanation:

= (1/a^7)^-3 * a^12 * a^119 * /a^7

= a^21 * (a^7) * a^7 * a^-2 * (a^7)^12 /a^7

= (3)³ * (3) * 3 * (3) * (3)^-2/7 * (3)^12 * 3^-1

= 3^(3+1+1+1-2/7+12-1)

= 3^(17-2/7)

= 3^(117/7)

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