Math, asked by millionerboy, 1 year ago

if a=7-4√3,find the value of √a+1/√a.

Answers

Answered by mysticd
17
a = 7 - 4root3-----(1)

1/a = 1/(7-4root3)
=(7+4root3)/(7-4root3)(7+4root3)
= (7+4root3)/(49-48)

= 7+4root3-----(2)

(root a + 1/root a)^2 = a+1/a + 2*a*1/a

= 7- 4root 3 +7+4 root3+2[from (1) and (2)]

=14

(root a+1/ root a) = root 14
Answered by BrainlyQueen01
33

Answer :


4


Step-by-step explanation :


Find the value of √a :


a = 7 - 4√3


a = 4 + 3 - 4√3


a = (2)² + (√3)² - 2 * 2 * √3


a = ( 2 - √3 )²


By rooting both the sides


√a = √(2 - √3)²


√a = 2 - √3


Find the value of 1 / √a :


√a = 2 - √3


1 / √a = 1 / 2 - √3


1 / √a = 1 / 2 - √3 * 2 + √3 / 2 + √3


1 / √a = 2 + √3 / 2² - √3²


1 / √a = 2 + √3 / 4 - 3


1 / √a = 2 + √3


Find √a + 1 / √a :


√a + 1 / √a = 2 - √3 + 2 + √3


√a + 1 / √a = 2 + 2


√a + 1 / √a = 4


Hence, the answer is 4.


Similar questions