Question

if a= 7;5 b 2;4 and c6;10 then show that ab = ac​

Answer 1

$a = (7, \: 5) \\ b = (2, \: 4) \\ c = (6, \: 10) \\ \\ ab = ac \\ \sqrt{ {(a1 - b1)}^{2} + {(a2 - b2)}^{2} } = \sqrt{ {(a1 - c1)}^{2} + {(a2 - c2)}^{2} }\\ \sqrt{ {( 7 - 2)}^{2} + {(5 - 4)}^{2} } = \sqrt{ {( 7 - 6)}^{2} + {(5 - 10)}^{2} } \\ \sqrt{ {(5)}^{2} + {(1)}^{2} } =\sqrt{ {(1)}^{2} + {( - 5)}^{2} } \\ \sqrt{25 + 1} = \sqrt{1 + 25} \\ \large{ \boxed{\bold{ \sqrt{26} = \sqrt{26} }}}\\ \\ \large{ \boxed{\bold{∴ \: \: \: ab = ac}}}$

Use distance formula to solve like this problems