Math, asked by aaryanaditya29, 2 months ago

if a=75 and b=98 find the number of zeros ending in a^a*b^b​
pls solve with steps including ​

Answers

Answered by zumba12
0

The number of zeroes ending in the equation is 346.

Given: The value of a and b.

To find: The number of zeros ending in a^{a}\times b^{b}

Step-by-step explanation:

  • A polynomial's zeros are the x values that meet the equation y=f\times x. The zeros of the polynomial are the values x for which the "y" value is equal to zero, and f(x) is a function of x.

Solution:

a=75 and b=98

a^{2}=75\times 2 = 150 and b^{2}=98\times2=196

a^{2}+b^{2}=150+196

346

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