Question

if (a-8)^2+(b-64)^2+(c-125)^2=0 then 3√abc=?​

Answer 1

Answer:

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Answer 2

we know that...

a² + b² + c² = 0

So

a = 0

b = 0

c = 0

Here....

a = a-8 =0....(a =8)

similarly

b = 64

c = 125 then cube root of 8×64×125 is 40

40 = 2×4×5 •°•(2×4 = 8 = a)

ans 5a