Question

if a = -8, b = -7,c = 6, then verify that (a+b) + c = a + (b + c)​

Answer 1

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$\tt \: (a + b) + c = a + (b + c) \\ \tt \: putting \: the \: values \: of \: a = - 8 \: \: \: \: \: b = - 7 \: \: \: \: \: c = 6 \\ \tt ( - 8 + ( - 7)) + 6 = - 8 + ( - 7 + 6) \\ \tt \: - 15 + 6 = - 8 + ( - 1) \\ \tt \: - 9 = - 9$

Answer 2

Answer:

Step-by-step explanation:

Given that,

a = - 8 , b = - 7 and c = 6.

L.H.S. = ( a + b ) + c

= [ - 8 + ( - 7 ) ] + 6

= ( - 8 - 7 ) + 6 (∵ + × - = - )

= - 15 + 6

= - 9

R.H.S. = a + ( b + c )

= - 8 + ( - 7 + 6 )

= - 8 + ( - 1 )

= - 8 - 1 (∵ + × - = - )

= - 9

∴ L.H.S. = R.H.S.

Hence it is proved.