Question

If a 8-digit number 30x558y2 is divisible by 88, then the value of (6x + 6y) is:. short trick​

Answer 1

ANSWER :-

Since the given number 30x558y2 is divisible by 88 , it is divisible by 8(11) so it is divisible by 11

and if a number is divisible by 11 , difference of sum of odd and even digits is divisible by 11

x + y + -7 = 11k

x + y = 11k + 7---------(a)

6(x+y) = 6(11k+7)

if k = 0 , 6(11k+7) = 42 and if k = 1 , equation (a) => x+y = 7 , y = 3 or 7 so that the number would be divisible by 88

x+y = 7 and to be divisible by 8 , y = 3 or 7

if y = 3 x = 4 and number is 30455832

if y = 7 x= 0 and number is 30055872

if u require the smallest number following those conditions , answer is 30055872

and 6(x+y) = 6x + 6y = 6(11k+7) = 6( 11(0)+7) = 42

Therefore the required number is 30055872 or 30455832 and the value of

6x+6y is 42

HOPE IT HELPS ✔️✔️✔️✔️