if a =9+2√6 and b =57/a,then what will be the value of a^2+b^2
Attachments:
Answers
Answered by
2
a^2=(9+2¦6)^2
=81+2×9×2¦6+4×6
=81+36¦6+24
=105¦6
b^2=(57/a)^2
=3249/105¦6
=1083/35¦6
a^2+b^2=105¦6+1083/35¦6
=(3675×6+1083)/35¦6
=(22050+1083)/35¦6
=23133/35¦6
=81+2×9×2¦6+4×6
=81+36¦6+24
=105¦6
b^2=(57/a)^2
=3249/105¦6
=1083/35¦6
a^2+b^2=105¦6+1083/35¦6
=(3675×6+1083)/35¦6
=(22050+1083)/35¦6
=23133/35¦6
satwikswager:
so thank you
your welcome
Similar questions