if a =9+4√5,find √a-1/√a
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Solution :
i ) a = 9 + 4√5
=> a = 9 + 2√(4 × 5)
=> a = 4 + 5 + 2 × √4 × √5
=> a = ( √4 )² + ( √5 )² + 2 × √4 × √5
=> a = ( √4 + √5 )²
=> √a = √4 + √5
=> √a = 2 + √5 ----( 1 )
ii ) 1/√a = 1/(2+√5 )
= ( √5 - 2 )/[(√5 + 2)(√5 - 2 )]
= (√5 - 2 )/[ (√5 )² - 2² ]
= (√5 - 2 )/( 5 - 4 )
= √5 - 2 ------( 2 )
Therefore ,
√a - 1/√a
= 2 + √5 + √5 - 2 [ from ( i ) & ( ii ) ]
= 2√5
••••
i ) a = 9 + 4√5
=> a = 9 + 2√(4 × 5)
=> a = 4 + 5 + 2 × √4 × √5
=> a = ( √4 )² + ( √5 )² + 2 × √4 × √5
=> a = ( √4 + √5 )²
=> √a = √4 + √5
=> √a = 2 + √5 ----( 1 )
ii ) 1/√a = 1/(2+√5 )
= ( √5 - 2 )/[(√5 + 2)(√5 - 2 )]
= (√5 - 2 )/[ (√5 )² - 2² ]
= (√5 - 2 )/( 5 - 4 )
= √5 - 2 ------( 2 )
Therefore ,
√a - 1/√a
= 2 + √5 + √5 - 2 [ from ( i ) & ( ii ) ]
= 2√5
••••
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