if a = 9-4 root 3 find the value of a square - 1 / a square
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Question not clear. Pls clarify
anvithavadlamudi:
if a= 9- 4 route 5 find the value of a2 [ a square ] - 1 \ a 2 [ a square ]
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a = 9 -4root5
a - 1/a =(9 -4root5) - (9 + 4root5)/1
a+1/a=(9 -4root5) + (9 + 4root5)/1
(a - 1/a)(a +1/a) ={(9 -4root5) - (9 + 4root5)}*{(9 -4root5) + (9 + 4root5) }
a^2 -(1/a)^2 = {18}{-8root5}
=-144root5
a - 1/a =(9 -4root5) - (9 + 4root5)/1
a+1/a=(9 -4root5) + (9 + 4root5)/1
(a - 1/a)(a +1/a) ={(9 -4root5) - (9 + 4root5)}*{(9 -4root5) + (9 + 4root5) }
a^2 -(1/a)^2 = {18}{-8root5}
=-144root5
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