+ If a = -9 and b = -6, show that i) (a - b) +(b-a) ii) {a + (-6)} = {(-b) + a}
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in the ques(II){a+(-6)}={(-b)+a}
since the value of a=-9 and that of b=-6;
LHS:
-9+(-6)=-9-6=-15
RHS:
6+(-9)=6-9=-3(since, the value of b given in the ques is already negative ie;(-6)
and then again in the (ii)part it is given {(-b) as b is two times negative it will become positive ,so we will write( +6)..
Step-by-step explanation:
and its not possible
LHS is not equal to RHS
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