If a = 9, b =-6 show that a - b # b-a
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a - b
9 - 6 = x
x= 3
b - a
6 -9 = x
x = -3
Therefore a-b is not equal to b- a because of the second time it is NEGATIVE THREE
9 - 6 = x
x= 3
b - a
6 -9 = x
x = -3
Therefore a-b is not equal to b- a because of the second time it is NEGATIVE THREE
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Answer:
a - b = (9) - (-6) = 9+6 = 15 ----1
b-a = (-6) - (9) = -6-9 = -15 ----2
∵ Equation 1 & 2 are not equal
∴ (a-b) ≠ (b-a)
Step-by-step explanation:
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