If a 9 digit number 32x4115y2 is divisible by 88, then the value of (4x-y) for the smallest possible value of y is
Answers
4x-y = 31 for smallest possible value of y i.e 1 if 32x4115y2 is divisible by 88
Step-by-step explanation:
9 digit number 32x4115y2 is divisible by 88
Divisible by 88 means divisible by 8 & 11
Divisibility rule for 8
If the last three digits of a whole number are divisible by 8, then the entire number is divisible by 8
5y2 divisible by 8
512 , 552 & 592 are Divisible by 8
=> y = 1 , 5 or 9
Smallest possible value of y = 1
Divisibility rule for 11
The Divisibility Rule of Eleven is that you must subtract and then add the digits in an alternating pattern from left to right
and resultant should be divisible by 11
3 - 2 + x - 4 + 1 - 1 + 5 - y + 2
= 4 + x - y
= 4 + x - 1 ( taking smallest possible value of y)
= 3 + x
x = 8 will make 3 + x divisible by 11
4x - y
= 4 * 8 - 1
= 31
4x-y = 31 for smallest possible value of y i.e 1
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