Math, asked by abhijeetvashish371, 1 year ago

If A = 90 B = 30° Sin(A+B)=SinA.CosB+CosA.SinB


hardik27: plz mark it brainliest

Answers

Answered by hardik27
0

LHS

sin (90+30)

=Sin (120)

=root3/2

RHS

sin90.cos30+cos90.sin30

1*(root3/2)+0*(1/2)

(root3/2)+0

=root3/2

Answered by KushalTiwari1
1

Answer :

L.H.S. =

= sin(A+B)

= sin(90°+30°)

= sin 90°+sin 30°

= sin 90° = 1

= sin 30° = 1/2

= 1+1/2

= 2+1/2

= 3/2

R.H.S. =

= sin A . cos B + cos A . sin B

= sin 90° . cos 30° + cos 90° . sin 30°

= sin 90° = 1

= cos 30° = √(3)/2

= cos 90° = 0

= sin 30° = 1/2

= 1 × √(3)/2 + 0 × 1/2

= √(3)/2 + 0

= √(3)/2

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