Question

If a-999,b-998,c-997,then find a²+b²+c²-ab-bc-ca?

Answer 1

Step-by-step explanation:

1. a^2+b^2+c^2-ab -bc-ca
2. by taking common group (a^2-ab) (b^2-bc) (c^2-ca)

a(a-b)+b(b-c)+c(c-a)

now a=999, b=998, c=997

999(999-998)+998(998-997)+997(997-999)

999(1)+998(1)+997(-2)

999+998-2*997

1997-1994=3

answer is 3

Answer 2

Answer:

3 is the correct information thanks