If a +/a=1 then a^3+1 =
Answers
Answered by
1
Step-by-step explanation:
a+1/a=1
cubing both sides
a^3+1+3a^2+3a/a^3=1
a^3+1+3a^2+3a=a^3
a^3+1=a^3-3a^2+3a
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Answered by
0
+1/+1=0
a
+
1
/
a
+
1
=
0
(2+1+)/=0
(
a
2
+
1
+
a
)
/
a
=
0
2++1=0
a
2
+
a
+
1
=
0
4−
a
4
−
a
=(3−1)
=
a
(
a
3
−
1
)
=((−1)(2++1))
=
a
(
(
a
−
1
)
(
a
2
+
a
+
1
)
)
=(−1)(2++1)
=
a
(
a
−
1
)
(
a
2
+
a
+
1
)
=(−1)(0)
=
a
(
a
−
1
)
(
0
)
=0
=
0
Therefore,4−=0
a
+
1
/
a
+
1
=
0
(2+1+)/=0
(
a
2
+
1
+
a
)
/
a
=
0
2++1=0
a
2
+
a
+
1
=
0
4−
a
4
−
a
=(3−1)
=
a
(
a
3
−
1
)
=((−1)(2++1))
=
a
(
(
a
−
1
)
(
a
2
+
a
+
1
)
)
=(−1)(2++1)
=
a
(
a
−
1
)
(
a
2
+
a
+
1
)
=(−1)(0)
=
a
(
a
−
1
)
(
0
)
=0
=
0
Therefore,4−=0
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