If a,a-2,3a are consecutive terms of an AP, then find value of a
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d = a - 2 - a
= -2
d = 3a - (a - 2)
= 3a - a + 2
= 2a + 2
2a + 2 = -2
2a = -2 - 2 = -4
a = -4 ÷ 2 = -2
-2 is the answer.
And the AP is -2, -4, -6,...
Hope this will be helpful.
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