Question

if a, (a-2) and 3a are in a AP. then what is the value of a​

Answer 1

$\boxed{ \bold{ \huge \red {\mathfrak{solution}}}}$

Given:

• a , a-2 and 3a are in AP

To find : a=?

For an AP common difference must be same so ,

=> t2-t1= t3-t2

=> a-2-a = 3a-a+2

=> -2=2a+2

=>-2-2=2a

=> a = -4/2

=> a = -2

Hence the value of a is

$\boxed{ \huge \bold \purple{ \mathfrak{ - 2}}}$

Answer 2

a-2-a= 3a-a+2

-2=2+2a

-4=2a

a= -2

the value of a is -2