If a (A)=20, n(B) = 50, n(AUB) = 60 and n (B`) = 20, find n(A u B) and n(u).
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Given: n(A) = 25; n(B) = 40; n (AU
B) = 50; n (B¹) = 25
Formula to be used:n (AUB) = n(A)
n (B)-n (ANB)
Substituting the given values in the above formula we get,
=> 50 = 25 + 40-n (AMB)
=> n(ANB) = 25+ 40-50 => n(ANB) = 65-50 = 15
Hence n (ANB) = 15 We also know that,
n(B ^ 1) = n(U) - n(B)
Substituting the values we get,
25 =n(U)- 40
=n(U)=40 + 25 = 65.
hence the universal set n(U) contains 65 elements
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