If A = a a ОО
10
Co o a
ООО
Then det (adj A) -
o ar I d) a ²
22
b) aq
solution:-
SI
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Answer:
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Step-by-step explanation:
Consider the following identity A(adjA)=∣A∣I. Thus comparing it with the above equation gives us ∣A∣=10
Now ∣adjA∣=∣A∣
n−1
where n is the order of the square matrix.
Here 'n' is 3, therefore, ∣adjA∣=∣A∣
3−1
=∣A∣
2
=10
2
=100
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