If A={A
a,b,c,d,e} B={a,c,e} and C={b,d,e}, then verify A-(BUC)=(A-B) N (A-C)
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B∩C={a,e}
A∩(B∩C)={a} −(i)
A∩B={a,c}
(A∩B)∩C={a} −(ii)
From (i) and (ii) A∩(B∩C)=(A∩B)∩C
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