If a,A,b are in AP prove that A=a+b÷2
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Given : a,b,c are in AP then prove that (a-c)^{2}=4(a-b)(b-c)
Let,
a=a_{1},b=a_{1} +d and c=a_{1} +2d where d is common different
Now,
LHS:-
(a-c)^{2}
=(a_{1} -a_{1}-2d)^{2}
=(-2d)^{2}
=4d^{2}
RHS:-
4(a-b)(b-c)
=4(a_{1}- a_{1}-d)(a_{1}+d-a_{1} -2d)
=4(-d)(-d)
=4d^{2}
∴ LHS=RHS
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