Question

If A/a=B/b=C/c=D/d,then
√(Aa)+√(Bb)+√(Cc)+√(Dd)/√a+b+c+d√A+B+C+D=

Answer 1

here's your answer bud!

Answer 2

Answer:

Given That

$\frac{A}{a}=\frac{B}{b}=\frac{C}{c}=\frac{D}{d}$

let,

$\frac{A}{a}=\frac{B}{b}=\frac{C}{c}=\frac{D}{d}=x$

Then

$</p><p>\frac{A}{a}=x\:\:\:\:→A=ax\\ \\ </p><p></p><p>\frac{B}{b}=x\:\:\:\:→B=bx\\ \\ </p><p></p><p>\frac{C}{c}=x\:\:\:\:→C=cx\\ \\ </p><p></p><p>\frac{D}{d}=x\:\:\:\:→D=dx$

to find:

$\frac{\sqrt{Aa}+\sqrt{Bb}+\sqrt{Cc}+\sqrt{Dd}}{(\sqrt{a+b+c+d})(\sqrt{A+B+C+D})}$

substitute in the question

$\frac{ \sqrt{ {a}^{2} x} + \sqrt{ {b}^{2} x} + \sqrt{ {c}^{2} x} + \sqrt{ {d}^{2} x} }{( \sqrt{a + b + c + d} )( \sqrt{ax + bx + cx + dx}) }$

a√x+b√x+c√x+d√x÷√(a+b+c+d)(ax+bx+cx+dx)

=√x(a+b+c+d)÷√(a+b+c+d)[x(a+b+c+d)]

=√x(a+b+c+d)÷√(a+b+c+d)√x√(a+b+c+d)

=√x(a+b+c+d)÷√x√(a+b+c+d)²

=(a+b+c+d)÷(a+b+c+d)

=1

hope this helps you please