If A/a=B/b=C/c=D/d; then √Aa+√Bb+√Cc+√Dd/√a+b+c+d.√A+B+C+D
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Answer:
Step-by-step explanation:
let,
Then
to find:
substitute in the question
a√x+b√x+c√x+d√x÷√(a+b+c+d)(ax+bx+cx+dx)
=√x(a+b+c+d)÷√(a+b+c+d)[x(a+b+c+d)]
=√x(a+b+c+d)÷√(a+b+c+d)√x√(a+b+c+d)
=√x(a+b+c+d)÷√x√(a+b+c+d)²
=(a+b+c+d)÷(a+b+c+d)
=1
hope this helps you please
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