if a={a, b},b={x, y},c={a, c, y} find (b-c)xa=(bxa)-(cxa)
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Step-by-step explanation:
( b-c ) = { x, y } - { a, c, y }
( b-c ) = {x}
(b-c)×a = {x} × {a, b}
= {(x,a) , (x,b)}
Now,
b×a= {x,y} × {a,b}
= {(x,a) , (x,b) , (y,a) , (y,b)}
c×a= {a,c,y} × {a,b}
= {(a,a) , (a,b) , (c,a) , (c,b) , (y,a) , (y,b)}
(b×a)-(c×a)= {(x,a) , (x,b) , (y,a) , (y,b)} - {(a,a) , (a,b) ,
(c,a) , (c,b) , (y,a) , (y,b)}
= {(x,a) , (x,b)}
Therefore, (b-c)×a = (b×a)-(c×a)
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