If A= (a,b) B=(x,y) C =(a,c,y)then verify (B-C)×A=(B×A)-(C×A)
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Step-by-step explanation:
*(B-C)={x,y}-{a,c,y}
(B-C)={x,y,a,c,}➡️1
(B×A)={x,y}×{a,b}a
(B×A)={(x,a) (x,b) (y,a) (y,b)}➡️2
(C×A)={(a,c,y)(a,b)}
(C×A)={(a,a)(a,b)(c,a)(c,b)(y,a)(y,b)}➡️3
(B-C)×A=(B×A)-(C×A)
(x,y,a,c)×(a,b)={(x,a)(x,b)(y,a)(y,b)}-{(a,a)(a,b)(c,a)(y,a)
(y,b)
{(x,a)(x,b)(y,a)(y,b)(a,a)(a,b)(c,a)(c,b)={(a)(x,b)(y,a)(y,b)}-{(a,a)(a,b)(c,a)(y,a)
(y,b)
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