Question

if A={a,b,c} B={2,3} C={a,b,c,d} then n[(A intersection C)×B] is

Answer 1

Answer:

6

hope it helps u.........

Answer 2

Answer:

In the given question, first we should find A intersection C. Then we should calculate the n[(A intersection C )×B]

Step-by-step explanation:

first we find A intersection C.

Intersection means that, the common values in the given sets. The symbol of intersection is ∩.

that is, $A=\left \{ a,b,c\right \}$

           $C=\left \{ a,b,c,d\right \}$

$A$ intersection $C$ $=A$∩$C$

         $A$∩$C$ $=$  $\left \{ a,b,c\right \}$ ∩ $\left \{ a,b,c,d\right \}$

common values in the two given sets are,$a,b,c$.

It should be written as,

         $A$∩$C$$= \left \{ a,b,c\right \}$

Next find the  $n[($$A$∩$C$$)$×$B$$]$

 $n[($$A$∩$C$$)$×$B$$]$ $=n($$A$∩$C$$)$×$B$

in the above formula,$n($$A$∩$C$$)$ is number of terms in   $A$∩$C$.

$n($$A$∩$C$$)$ $=3$

similarly,$n(B)$ is the number of terms in $B$.

$n(B)=2$

$n[($$A$∩$C$$)$×$B$$]$ $=n($$A$∩$C$$)$×$B$

                   $=3$ × $2$

$n[($$A$∩$C$$)$×$B$$]$ $=6$

$n[(A$ intersection $C)$ × $B]=6$