If A=(a,b,c,d) and B=(b,d,e,f), then prove that (AUB)-(AnB)=(A∆B).
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Step-by-step explanation:
(AUB)-(AnB)=(AnB)'
A = {a, b, c, d}
B = {b, d, e, f}
(AUB) - (AnB) = {a, b, c, d, e, f} - {b, d} = {a, c, e, f}
(AnB)' = {a, c, e, f}
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