Question

if A=(a,b.c.d). find p(A)​

Answer 1

Answer:

Let first term =a and common difference = d

∴A=(

2

10

)[2a+(10−1)d]

=5(2a+9d)

now

B=(

2

10

)[2a

6

+(10−1)d]

=5[2{a+5d}+9d]

=5[2a+19d]

nowB−A=200

or5×10d=200

∴d=(

50

200

)=4

andA+B=860

5(2a+9d)+5(2a+19d)=860

or20a+140d=860

∴a=15

thena

15

=a+14d

=15+56

=71

Answer 2

The list of all subsets of a,b,c,d is ϕ ,{a},{b},{c},{d},{a,b},{a,c},{a,d},{b,c},{b,d},{c,d},{a,b,c},{a,b,d},{a,c,d},{b,c,d},{a,b,c,d}