Question

If A×A has 16 elements , S={(a,b)belongs to A×A:a<b} ; (-1,2) and (0,1) are two elements of S, then find the remaining elements of S.​

Answer 1

Answer:

{(-1, 0), (-1, 1), (0, 2), (1, 2)}

Step-by-step explanation:

n(A × A) = 16 ⇒ n( A) = 4

S ={(-1, 0), (-1, 1), (0, 2), (1, 2)}