Question

If A = { α; a is a natural number, 2<5 and 2 777 a>7² then n (A) is (1) 1 (m) o (m) 2 (iv) 3​

Answer 1

Answer:

We have, 5

2

−1

2

=25−1=24

7

2

−5

2

=49−25=24

73−7

2

=73−49=24

This shows that the difference of a term and the preceding term is always same. Hence, the given sequence forms an AP.