If A=[a1 b1 c1
a2 b2 c2
a3 b3 c3]is non singular,prove that A^-1=Adjoint A/determinent A
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Step-by-step explanation:
Given
> TAA is a non-singular matrix,
then
A- a b c
La, &
le
45
Х
MATHS
and soon..
if A
a & Ta, a ca]
A.adja = a, b, c Cu Ca La, b, 6. Ca C
Tdet 4 0 0 det A 0 = det A
deta because A is invertible, detA=0.
1 1 A(ad4)-1
det 4
4
1
detA
ad 4 = 1
1 adjA =
det 4
adjA det A
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