Question

If A =a1i +b1j and B=a2i +b2j, the condition that they should meet such that they are perpendicular to each other is:
a. a1/b1 = -b2/a2 b) a1b1 = a2b2 c) a1/a2 = -b1/b2 d)None of the above.

Answer 1

Answer:

option a.

Explanation:

for vectors to be perpendicular, the dot product is zero.

(a1i+b1j).(a2i +b2j) = a1a2+b1b2= 0

a1/b1 = -b2/a1

Answer 2

Explanation:

cos theta = |A| •|B|/√(a1^2+b1^2)•√(a2^2 +b2^2)

→cos90= (a1a2+b1b2)/√(a1^2+b1^2)•√(a2^2+b2^2)

→0=a1a2 + b1b2

→a1a2= -b1b2

→ a2/(-b2)= b1/a1

→ (-b2)/a2= a1/b1

#11 starter

Sorry , it there is mistake because I just entered into class 11 so I am not much confident over any chapter