Question

If A=a2+6, B=3a2+a+2 and C=a2+4a, then find A+B-C.

Answer 1

Answer:

A=a2+6

B=3a2+a+2

C=a2+4a

A + B + C = (a2+6) + (3a2+a+2) + (a2+4a)

= a2+6 + 3a2+a+2 + a2+4a

= 1a^2 + 3a^2 + 1a^2 + 1a + 4a + 6 + 2

= 5a^2 + 5a + 8

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