Question

if A = [ ab b²] then A² is matrix
[ -a² ab]​

Answer 1

Step-by-step explanation:

To show

: A² = 0

Solution

Given that

ab 6² -a²-ab H: A =

Now,

: A²

= ΑΧΑ

ab 6² -a²-ab ab 62 -a² - ab] [a²b²-a²b² ab³ - ab ³ -ba³ + ba³-a²b² + a²b² = =

=

A² = 0

Hence, Proved