If a ∆ABC,a=4,b=3,c=5 then cosA=
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CosA=5/4 I think it is answer
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Answer:
Cos A=3/5
Step-by-step explanation:
We know that ∆ABC is a right angled triangle from sides a=4,b=3,c=5
The side opposite to angle A is a=4
The side adjacent to angle A is b=3
Cos A=Adj/Hyp
Cos A=b/c=3/5
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