Math, asked by Mahu9816, 7 months ago

If a ∆ABC,a=4,b=3,c=5 then cosA=

Answers

Answered by Prashnadangol12
0

CosA=5/4 I think it is answer

Answered by prabhukiransurisetti
0

Answer:

Cos A=3/5

Step-by-step explanation:

We know that ∆ABC is a right angled triangle from sides a=4,b=3,c=5

The side opposite to angle A is a=4

The side adjacent to angle A is b=3

Cos A=Adj/Hyp

Cos A=b/c=3/5

Hope it helps you.

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