Math, asked by sachin4014, 11 months ago

If A ABC A PQR and ar (ABC) = 81 cm", ar (APQR) = 121 cm² and altitude AD = 9 cm. Find the
altitude PM

Answers

Answered by raghu3754
13

Answer:

given

(ABC)= 81

(APQR) =121

AD=9

PM=11

Answered by JeanaShupp
31

The length of the altitude PM is 11 cm.

Explanation:

Given : ΔABC ≈ Δ PQR

ar (ABC) = 81 cm²

ar (PQR) = 121 cm²

Length of altitude AD = 9 cm

To find : altitude PM

If two triangles are similar then the ratio of the area of the triangles is equal to the ratio of the square of the corresponding altitudes.

\dfrac{\text{ar (ABC)}}{ar(PQR)}=\dfrac{(AD)^2}{(PM)^2}

\dfrac{81}{121}=\dfrac{9^2}{PM^2}\\\\ \dfrac{81}{121}=\dfrac{81}{PM^2}\\\\PM^2=121\\\\ PM=\sqrt{121}=11

Hence, the length of the altitude PM is 11 cm.

# Learn more :

If triangle ABC is similar to the triangle QRP, ar(ABC)/ar(PQR)= 9/4, AB=18 cm BC=15 cm, then PR= ?

https://brainly.in/question/2049181

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