Math, asked by Adhyatma1172, 10 months ago

If A = (aij) is a 2×3 matrix , such that aij= (-i+2j)²/5 .then a23 is?

Answers

Answered by Anonymous
4

Answer:a23=(-2+6)^2 /5=16/5

Step-by-step explanation:

Answered by SaurabhJacob
2

Given:

A = (aij) is a 2×3 matrix

aij= (-i+2j)²/5

To Find:

a23

Solution:

The representation of a matrix in the form aij

which gives the term of each matrix

where,

i is the number of rows and j is the number of columns

According to question

aij= (-i+2j)²/5

We have to find a23

i = 2 and j=3

putting the value of i and j in (-i+2j)²/5

a23 = (-2+(2×3))²/5

      =16/5

      =3.2

Hence, a23 is 3.2

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