If A = (aij) is a 2×3 matrix , such that aij= (-i+2j)²/5 .then a23 is?
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Answer:a23=(-2+6)^2 /5=16/5
Step-by-step explanation:
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Given:
A = (aij) is a 2×3 matrix
aij= (-i+2j)²/5
To Find:
a23
Solution:
The representation of a matrix in the form aij
which gives the term of each matrix
where,
i is the number of rows and j is the number of columns
According to question
aij= (-i+2j)²/5
We have to find a23
i = 2 and j=3
putting the value of i and j in (-i+2j)²/5
a23 = (-2+(2×3))²/5
=16/5
=3.2
Hence, a23 is 3.2
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