If a(alpha) and b(beta) are zeroes of a polynomial x² - x - 12, then the value of (a+b) is
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Answer:
a+b=-coefficient of x/ coefficient of x^2
Answered by
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Answer:
(a + b) = 1
Step-by-step explanation:
Let, F(x) = x² - x -12
For zeroes F(x) = 0
x² - x - 12 = 0
x² -(4 - 3)x - 12 = 0
x² - 4x + 3x - 12 = 0
x(x - 4) + 3(x- 4) = 0
(x - 4)(x + 3) = 0
if, (x - 4) =0
x = 4
if, (x + 3) = 0
x = -3
then, a = 4 and b = -3
a + b = 4 + (-3)
= 4 - 3
= 1
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