Question

If a&b are the roots of the quadratic equation x^2-p(x+1)-c,then find the value of (a+1)& (b+1)

Answer 1

x² - p(x+1)-c = x² -px-p -c

compare it with ax²+bx+c =0

a= 1, b= -p , c= -p-c

α and β are two zeroes

i) sum of the zeros= -b/a

α+β = - (-p)/1= p -----(1)

ii) product of the zeroes = c/a

αβ = (-p-c) /1 = -p-c -----(2)

now take 

lhs = (α+1)(β+1)

= α(β+1) +1(β+1)

=αβ +α +β +1

=-p-c+p+1  [from (2) and (1) ]

= -c+1

=1 -c

=RHS

Read more on Brainly.in - https://brainly.in/question/1171203#readmore

Answer 2

x² - p(x+1)-c = x² -px-p -c

compare it with ax²+bx+c =0

a= 1, b= -p , c= -p-c

α and β are two zeroes

i) sum of the zeros= -b/a

α+β = - (-p)/1= p -----(1)

ii) product of the zeroes = c/a

αβ = (-p-c) /1 = -p-c -----(2)

now take 

lhs = (α+1)(β+1)

= α(β+1) +1(β+1)

=αβ +α +β +1

=-p-c+p+1  [from (2) and (1) ]

= -c+1

=1 -c

=RHS