Question

: If a & b are the two zeroes of the polynomial x^2 - p(x+1) -c such that (a+1)(b+1)=0.
then what is the value of c?

Answer 1

Answer:

if a,b are zeroes

then they are roots of a quadratic eq

then, a+b=p

ab= -c-p

(a+1)(b+1)=ab+a+b+1=0

then,p-c-p+1=0

c=1