if a & b are the zeroes of the quadratic polynomials f (x)=x2-5x+k, such that a-b=1,then find the value of k .
Answers
Answered by
10
Hey user !!
Here is your answer !!
__________________________________________________⭐
↪Here a = 1 , b = -5 ,c = k
↪Sum of zeroes = -b / a = -5 / 1
↪Product of zeroes = c / a = k / 1
↪Now,
↪a - b = 1
↪Squaring both sides
↪(a - b) ^2 = 1 ^2
↪(a+ b)^2 - 4 ab = 1
↪5 ^2 - 4 (K) = 1
↪25 - 4k = 1
↪- 4k = 1 -25
↪- 4k = -24
↪k = 6
Hope it is satisfactory :-)
_______________________________________________⭐
Here is your answer !!
__________________________________________________⭐
↪Here a = 1 , b = -5 ,c = k
↪Sum of zeroes = -b / a = -5 / 1
↪Product of zeroes = c / a = k / 1
↪Now,
↪a - b = 1
↪Squaring both sides
↪(a - b) ^2 = 1 ^2
↪(a+ b)^2 - 4 ab = 1
↪5 ^2 - 4 (K) = 1
↪25 - 4k = 1
↪- 4k = 1 -25
↪- 4k = -24
↪k = 6
Hope it is satisfactory :-)
_______________________________________________⭐
Similar questions