If a & B are the zeros of
a quadralic polynomial such
that a+b= 24 and a-b=8 . Find the quadratic polynomial having a and b as it's zeros
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Step-by-step explanation:
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Step-by-step explanation:
a+b=24
a-b=8
Solving by adding both the equation we get
a=16 and b=8
Product of zeroes(16&8)=16*8
=128
Therfore, required polynomial =x^2+sumx+product
=x^2+24x+128
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