if a & B are the zeros of the quadratic polynomial f (x) = px² + qx + r , then the value of (1 / pa + q) + ( 1 / pB + q)
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f(x)=px2 +qx +r;
sum of the roots= alpha+Beta =(-q/p);
product of the roots =alpha*beta= r/p;
Put these values in the expression
1/ (p.alpha+q) + 1/ (p.beta+q)
On solving you will get = q/(pr)
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