Question

if a & B are the zeros of the quadratic polynomial f (x) = px² + qx + r , then the value of (1 / pa + q) + ( 1 / pB + q)​

Answer 1

f(x)=px2 +qx +r;

sum of the roots= alpha+Beta =(-q/p);

product of the roots =alpha*beta= r/p;

Put these values in the expression

1/ (p.alpha+q) + 1/ (p.beta+q)

On solving you will get = q/(pr)