Question

if a&b are the zeros of x^2-4+3 then find the value of a^4 b^3 +a^3 b^4
plz hlep me​

Answer 1

Correct Question:

• If α and β are zeros of x² - 4x + 3, then find the value of α⁴β³ + α³β⁴

Solution:

Given,

→ x² - 4x + 3 = 0

Comparing with ax² + bx + c = 0, we get,

→ a = 1, b = -4, c = 3

We know that,

→ α + β = -b/a

→ αβ = c/a

So,

→ α + β = -(-4)/1

→ α + β = 4

Now,

→ αβ = 3/1

→ αβ = 3

Therefore,

α⁴β³ + α³β⁴

= α³β³(α + β)

= (αβ)³(α + β)

= 3³ × 4

= 108

So, the value of α⁴β³ + α³β⁴ is 108 (Answer)

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