If A & B can do a job in 8 days and B & C can do the same job in 12 days. If A, B & C work together they can finish the job in 6 days. In how many days can A & C finish the job?
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Answer:
8 days
Step-by-step explanation:
Using LCM method:
total work is equal to LCM of 8, 12 & 6 i.e. 24 units
A+B=8 Days; B+C=12 Days; A+B+C=6 Days.
So, A+B complete 3 parts per day. (24/8=3)
B+C complete 2 parts per day.(24/12=2)
A+B+C complete 4 parts per day. (24/6=4)
Now, 2(A+B+C)−(A+B)−(B+C)=(A+C)
=>(A+C)=2*(4)−3−2
=>(A+C)=3 parts per day.
A & C will take 8 days to complete.(24/3=8)
Hope it helps you
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